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Add parameter in UNIX from date

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# 15  
Old 10-16-2017
Arithmetic operations expect NUMBERS to act upon, which e.g. 16/10/2017 is not. For which of your operations do you get that error? And, what is $5? Plus, why the square brackets?
# 16  
Old 10-16-2017
Hi Rudic...Thanks for your help. I am using below code to get the number of days.

Code:
today_date=$(date +%d/%m/%Y) mm=$5 dd=$(date -d"$mm" +%d/%m/%Y) echo [[ $(( ($today_date - $dd) / (60 * 60 * 24) ))]]

. So I am getting below error " value too great for base (error token is "08")" I am having Todays Date: 16/10/2017 and Date From : 11/08/2017. I tried with adding 10# to the both the dates but still getting same error.
Also tried :
Code:
 echo [[ $(( (10#$today_date - 10#$dd) / (60 * 60 * 24) ))]]

Thanks in advance.

---------- Post updated at 05:39 AM ---------- Previous update was at 05:27 AM ----------

$5 is parameter I am passing from front end i.e.Date from(11/08/2016). I am passing 2 dates and trying to find out the no. of days.

Moderator's Comments:
Mod Comment Please start using code tags correctly - check your post before posting, and format your code here as it is in your script
Last edited by Scott; 10-16-2017 at 08:19 AM.. Reason: Fixed code tags AGAIN (did not reformat code)
# 17  
Old 10-16-2017
Date differences
Hi.

Post #4 in thread Months difference between 2 dates

illustrates one solution. The time in days for this instance would be:
Code:
dateutils.ddiff -f "%d days" "today" -i "%m/%d/%Y" "11/08/2016"

producing:
Code:
-342 days

Some details for ddiff:
Code:
dateutils.ddiff Compute duration from DATE/TIME (the reference date/ti... (man)
Path    : /usr/bin/dateutils.ddiff
Package : dateutils
Home    : http://www.fresse.org/dateutils
Version : 0.3.1
Type    : ELF64-bitLSBsharedobject,x86-64,version1(S ...)
Help    : probably available with -h,--help

On a system like:
Code:
OS, ker|rel, machine: Linux, 3.16.0-4-amd64, x86_64
Distribution        : Debian 8.9 (jessie) 
dateutils.ddiff ddiff 0.3.1

Best wishes ... cheers, drl
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