Creating file and passing argument to a command

 
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# 1  
Old 02-03-2017
Creating file and passing argument to a command

Hi All,

I am having command to run which will take argument as input file. Right now we are creating the input file by cat and executing the command


Code:
 ftptransfer -i input file 
cat >input file
file1
file2
cntrl +d


Is there a way I can do that in a single command like

Code:
ftptransfer -i  cat > file1 file2


Thanks
Arun
# 2  
Old 02-03-2017
I don't know if you utility ftptransfer can process stdin. If so you could use a "here document" .

For example (I do not know filetransfer, so it is just a guess if it works that way, you would need to check the manual):
Code:
ftptransfer << EOF
file1
file2
EOF

If you are using modern bash, ksh93 or zsh you could also try process substitution, something like:
Code:
ftptransfer -i <(printf "%s\n" file1 file2)

or turn a here document in to a "file"

Code:
ftptransfer -i <(cat << EOF
file1
file2
EOF
)

or an example using a here-string

Code:
files="file1
file2"

ftptransfer -i <(cat <<< "$files")


Last edited by Scrutinizer; 02-03-2017 at 04:27 PM..
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