UNIX for Beginners Questions & Answers

I have this code below that only prints out certain columns from the first two rows (doesn't affect rows 3 and beyond). How can I do the same on a partial header pattern “G_TP” instead of having to know specific column numbers (e.g. 374-479)? I've tried many other commands within this pipe with no luck.

I have 53 columns out of 600 or so that the header pattern begins with “G_TP”, but the columns may change positions and if that happens, my method below won't work any longer because of the fixed column number “374-479”.

Code:

(head -n 2 file.csv | cut -d ',' -f 374-479; tail -n +3 file.csv) > file.txt

Thank you!

Please post a reasonably reduced but representative sample of your input and the related output.

Here are the full input (..fsw1952) and output (..fsw1953) files attached. As you can see, after I run the code from my initial post, the output file (..fsw1953) only contains the header pattern "G_TP" columns in the first two rows only (header and data).

This is the correct output, but I just want my code to perform this based on partial pattern instead of fixed column numbers (as mentioned before).

Thanks!

Try:

Code:

#!/bin/ksh
ERE=${1:-"^G_TP"}
file=${2:-"f16_may_25_16_23_04_fsw1952.txt"}

awk -F, -v ERE="$ERE" '
NR == 1 {
	for(i = 1; i <= NF; i++)
		if($i ~ ERE)
			of[++nof] = i
}
NR < 3 {for(i = 1; i <= nof; i++)
		printf("%s%s", $of[i], (i == nof) ? "\n" : FS)
	next
}
1' "$file"

Although written and tested using a Korn shell, this should work with any shell supporting POSIX shell syntax. If you want to try this on a Solaris/SunOS system, change awk to /usr/xpg4/bin/awk or nawk.

When this script is run with no operands, it produces output identical to the file you attached named f16_may_25_16_23_04_fsw1953.txt.

Okay, thank you! Let me try this and get back with the results.

---------- Post updated at 05:19 PM ---------- Previous update was at 04:59 PM ----------

Don, that script seemed to work very well!

Thank you for your time!