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# 1  
Old 12-06-2008

helllo every body ..
hope you are having good time programming in unix .

here is a little problem faced me :
setenv("myvar","bla bla",1); 

printf("%s\n", getenv("myvar"));

will print :
bla bla ..

how can i get the value of grep into my program ?
what i figurd out that is after

myvar will have the same old value,
system("myvar=hello; echo $myvar");

will pring hello without changing myvar value.
# 2  
Old 12-06-2008
The system function runs the command in a subshell (child) and parent shells don't inherit variables of childs.

# 3  
Old 12-06-2008
what if you invoke your script with a "source scriptname" ?
# 4  
Old 12-06-2008
Originally Posted by npatwardhan
what if you invoke your script with a "source scriptname" ?
you mean running
VAR=$( ...)

in seperate script ?
it dosn't work Smilie

Last edited by max_475; 12-06-2008 at 02:09 PM..
# 5  
Old 12-06-2008
Originally Posted by Franklin52
The system function runs the command in a subshell (child) and parent shells don't inherit variables of childs.

i thought something like this is happning,
do you think learning more about "fork" will help me?
# 6  
Old 12-07-2008
Use the popen function, this is an example to set a environment variable with a value fetched with a shell command:

#include <stdio.h>
#include <stdlib.h>

int main (int argc, char *argv[])
        FILE *pipein;
        char readbuf[80], Myvar[80];

        if ((pipein = popen("pwd", "r")) == NULL)


        fgets(readbuf, 80, pipein);

        setenv(Myvar, readbuf, 1);

        printf("%s", getenv(Myvar));



# 7  
Old 12-13-2008
I'm from the ubuntuforum, we used to have a "thanks" buttom to express our appreciation!

Thank you, works like magic.
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