Regular Expression Error in AWK


 
Thread Tools Search this Thread
Top Forums UNIX for Advanced & Expert Users Regular Expression Error in AWK
# 1  
Old 06-16-2008
Regular Expression Error in AWK

I have a file "fwcsales_filenames.txt" which has a list of file names that are supposed to be copied to another directory. In addition to that, I am trying to extract the date part and write to the log.

I am getting the regular expression error when trying to strip the date part using the "ll" command. But I was able to count the number of records for each filename inside the list.

Please let me know what mistake I am doing here while usine AWK to print the date part.

Code:
while read FILENAME
do
  cp ${FTP}/$FILENAME ${EXPORT}/nz.$FILENAME
  if [ $? -eq 0 ]
    then
      let NUM_COPIED=`expr $NUM_COPIED+1`
     DAY=$(ll $FTP | awk '/$FILENAME/ {print $6 $7 substr($8,1,5)}' )
     echo "*** FTP file from $DAY "
     RECORDS=$(cat $FTP/$FILENAME |wc -l )
     echo '*** Number of $FILENAME records = ' $RECORDS
  fi
  done < ${FTP}/fwcsales_filenames.txt

HTML Code:
Output:
awk: There is a regular expression error.
        Invalid pattern.
 The input line number is 1.
 The source line number is 1.
*** FTP file from
*** Number of $FILENAME records =  256
# 2  
Old 06-16-2008
Oooops...I found the answer....When I put quotes it worked...Sorry!!

Code:
DAY=$(ll $FTP/$FILENAME | awk '"$FILENAME" {print $6 $7 substr($8,1,5)}' )

Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Problem with Regular expression in awk

Hi, I have a file with two fields in it as shown below 14,30 28,30 16,30 22,30 21,30 3,30 Fields are separated by comma ",". I've been trying to validate the file based on the condition "each field must be a numeric value" I am using HP-UX OS. I have tried the following awk... (4 Replies)
Discussion started by: meetsriharsha
4 Replies

2. Shell Programming and Scripting

awk regular expression

Hello, I have big files which I wanna filter them based on first column. first column should be one of these strings: chr2L || chr2R || chr3L || chr3R || chr4 || chrX and something like chr2Lh or chrY or chrM3L is not accepted. I used the following command: awk '{ if ($1=="chr2L" ||... (5 Replies)
Discussion started by: @man
5 Replies

3. Shell Programming and Scripting

Help with awk script (syntax error in regular expression)

I've found this script which seems very promising to solve my issue: To search and replace many different database passwords in many different (.php, .pl, .cgi, etc.) files across my filesystem. The passwords may or may not be contained within quotes, single quotes, etc. #!/bin/bash... (4 Replies)
Discussion started by: spacegoose
4 Replies

4. Programming

Perl: How to read from a file, do regular expression and then replace the found regular expression

Hi all, How am I read a file, find the match regular expression and overwrite to the same files. open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat"; open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat"; while (<DESTINATION_FILE>) { # print... (1 Reply)
Discussion started by: jessy83
1 Replies

5. Shell Programming and Scripting

Regular expression in AWK

Hello world, I was wondering if there is a nicer way to write the following code (in AWK): awk ' FNR==NR&&$1~/^m$/{tok1=1} FNR==NR&&$1~/^m10$/{tok1=1} ' my_file In fact, it looks for m2, m4, m6, m8 and m10 and then return a positive flag. The problem is how to define 10 thanks... (3 Replies)
Discussion started by: jolecanard
3 Replies

6. Shell Programming and Scripting

Awk regular expression - I need exactly 1 occurrence of it

Hi all, I am processing a file with awk that looks like this: " 0.0021 etc 0.0123 etc 0.1234 etc ... 0.5324 etc 0.5434 etc 0.6543 etc ... 1.0344 etc 1.1344 etc ... 1.5345 etc 1.5632 etc " I need to print out only the lines that have '0' or '5' after the comma, plus I need only... (11 Replies)
Discussion started by: ioannisp
11 Replies

7. Shell Programming and Scripting

Regular expression query in AWK

Hi, I have a string like this-->"After Executing service For 10 Request" in this string i need to extract "10". the contents of the string is variable and "10" appears before "For" and after "Request" i.e, in this format "For x Request" I need to extract the value of x. How to do this in AWK?... (10 Replies)
Discussion started by: omprasad
10 Replies

8. Shell Programming and Scripting

need help guys for Regular expression in awk

Hello Experts, Please help me to cope with the following problem I ve patterens like Input Noptx(5) // remain the same -*Nop(3); Nop(9); --Nop(8); // remain the same d3 **---Nop(7); //remain the same d3 **---Nop(7); *--Nop(6); --**Nop(5); -Nop(4); Nop(3); - represents a space... (2 Replies)
Discussion started by: user_prady
2 Replies

9. UNIX for Dummies Questions & Answers

regular expression and awk

I can print a line with an expression using this: awk '/regex/' I can print the line immediately before an expression using this: awk '/regex/{print x};{x=$0}' How do I print the line immediately before and then the line with the expression? (2 Replies)
Discussion started by: nickg
2 Replies

10. Shell Programming and Scripting

awk and regular expression

Ive got a file with words and also numbers. Bla BLA 10 10 11 29 12 89 13 35 And i need to change "10,29,89,25" and also remove anything that contains actually words... (4 Replies)
Discussion started by: maskot
4 Replies
Login or Register to Ask a Question