I opened a simple text file by vi. I then started another shell, and did fuser myFile. I expected it to show the pid of the vi session that had that file open, but it just returned a blank.
then I can see a whole bunch of processed, one of which is my vi with my file open.
But I don;t want that.
I want to do
Code:
fuser myFile.ksh
as I only want to see if myFile.ksh is open. Am I missing something here?
thanks
===============================================
Hey,
Try to use following..
MYPATH="/clocal/user/dir1/dir2/"
for file_dir in `find $MYPATH -amin -1`
do
echo `fuser -uf "$file_dir" ` >> temp.txt.$$
echo " $file_dir is being accessed" >> temp.txt.$$
done
or
fuser -uf /dir1/dir2/file1
It perfectly works. and it shows the name of the user, who has accessed the file.
Catch : fuser returns a process id !! Below command stores the process id, thats being returned by fuser command.
I opened a simple text file by vi. I then started another shell, and did fuser myFile. I expected it to show the pid of the vi session that had that file open, but it just returned a blank.
why would this be?
thanks
-------------------------------------------
hey,
for more help you can visit my post under the same forum:
"awk and fuction (recursion) !! Urgent !! "
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-------------------------------------------------
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Subject="File accessed in last... (6 Replies)
02-25-2008
