UNIX for Advanced & Expert Users

Hi I am having the script which contains more functions. I want to exit the function if any failure. I tried with exit - the session itself is getting logged out. How can i fix this issue?

It would help if you explained how you were using the script and it's functions.

It may depend on how you invoke the script.
If you invoke the script as . ./yourscript.sh, then it would exit from the session as well.

Hi
function imple()
{
if [ ! -d $sourcedir ] ; then
echo " $sourcedir is not found from the release directory $RELPATH " | tee -a $REPLIMPLOG
exit // This exit is throwing me out of the session
elif [ ! -d $destdir ] ; then
echo " $destdir is not available in the production environment. " | tee -a $REPLIMPLOG
exit // This exit is throwing me out of the session
elif [ ! -d $destbak ] ; then
echo " $destbak is not available in the production environment. " | tee -a $RELIMPLOG
exit // This exit is throwing me out of the session
else
valid_flag=0
fi
}

I hope this is enough for u.

That is what exit does, it terminates the current process.

How are you invoking this script?

This function is from the script only. The big script is having multiple functions. This function is one among that. This is not seperate script. (This is function)

Yes, but as porter asked, how are you invoking the big script? Are you running it as: /path/to/script or 'cd /path/to/script; ./script' or what?