Weird scenario with Awk

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# 1  
Old 10-23-2007
Weird scenario with Awk

Guys, this one is rather odd. I've got an array of numbers, and I'm trying to select only the records with the string "Random" in the 4th column. I'm using awk in this format:

awk '{ if (( $6 -eq Random )) print $0 }'

For some odd reason, this is simply giving me the list of all the entries in my file. Can anyone help?

# 2  
Old 10-23-2007
awk '{ if (( $6 == "Random" )) print $0 }'

thanks y'all

# 3  
Old 10-25-2007
you had mentioned it as 4th column and making use of $6 in awk command.

Typo ? Smilie
# 4  
Old 10-25-2007
Originally Posted by Khoomfire
awk '{ if (( $6 == "Random" )) print $0 }'

thanks y'all

if this is just want you want, then it can be shortened
awk '$6=="Random"' "file"

# 5  
Old 10-29-2007
$6 exactly random

awk '$6=="Random" {print}'

$6 contain random

awk '$6~/Random/ {print}'

have a nice day Smilie
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