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Passing a variable into an awk script

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# 1  
Old 09-05-2006
Passing a variable into an awk script
Hello all,
I'm trying to run a script of this format -

for i in $(cat <file>); do
grep $i <file1>|awk '{print $i, $1, $2}'

It's not working - does anyone know how this can be done?

Khoom
# 2  
Old 09-05-2006
Quote:
Originally Posted by Khoomfire
Hello all,
I'm trying to run a script of this format -

for i in $(cat <file>); do
grep $i <file1>|awk '{print $i, $1, $2}'

It's not working - does anyone know how this can be done?

Khoom
Code:
#!/bin/ksh
for i in $(< file ); do
   nawk -v myI="${i}" '$0 ~ myI { print myI, $1, $2 }'
done

# 3  
Old 09-05-2006
Quote:
Originally Posted by vgersh99
Code:
#!/bin/ksh
for i in $(< file ); do
   nawk -v myI="${i}" '$0 ~ myI { print myI, $1, $2 }'
done

ksh: nawk: not found


<sigh>
# 4  
Old 09-05-2006
try with plain 'awk'
# 5  
Old 09-05-2006
Quote:
Originally Posted by Khoomfire
Hello all,
I'm trying to run a script of this format -

for i in $(cat <file>); do
grep $i <file1>|awk '{print $i, $1, $2}'

It's not working - does anyone know how this can be done?

Khoom
I have it now - thanks to vgersh99 for the inspiration

for i in $(cat <file>); do
grep $i <file1>|awk -v string=$i '{print string, $1, $2}'
# 6  
Old 09-05-2006
  1. why do you need a 'cat'?
  2. why do you need a 'grep'?
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