How to replace special characters?

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# 1  
Old 04-21-2017
How to replace special characters?

Hi Team,

I have data like this.


Would like to add zero (0) before the decimal point where there is no zero as


How to replace |*|. with |*|0.

I tried below command which didn't work

echo '|*|.5|*|0.2|*|A.B|*' | sed 's/\|\*\|\./\|\*\|0\./g'


Last edited by Corona688; 04-21-2017 at 04:47 PM..
# 2  
Old 04-21-2017
$ echo '|*|.5|*|0.2|*|A.B|*|' | sed 's/|\./|0\./'

# 3  
Old 04-21-2017
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# 4  
Old 04-21-2017
Why use sed?
Longhand using OSX 10.12.4, default bash terminal.
(Assumption bash is available.)
Interactive mode is a great way to test.
Last login: Fri Apr 21 22:35:25 on ttys000
AMIGA:amiga~> STRING='|*|.5|*|0.2|*|A.B|*|'
AMIGA:amiga~> PREFIX="|*|0"
AMIGA:amiga~> echo "$PREFIX${STRING:3}"
AMIGA:amiga~> _

This User Gave Thanks to wisecracker For This Post:
# 5  
Old 04-22-2017
Post#4 requires the match at the beginning of the string.
Post#2 does only one substitution and also does it for A.B.
The following requires a digit after the dot, and because it is part of the match must mark it in \( \) and put it back via a back-reference. Also it does the substitution globally.
echo '|*|.5|*|0.2|*|A.B|*|' | sed 's/|\(\.[0-9]\)/|0\1/g'

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