Need help to extract part of the string


 
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# 1  
Old 05-14-2015
Need help to extract part of the string

Hi,

I have a string with name as 20140412-s1-Potopolive_promos_20140412. So I want to extract only Potopolive string. Could you please help me the command.

O/p : Potopolive


Thx in advance

Last edited by rbatte1; 05-14-2015 at 08:26 AM.. Reason: Added ICODE tags
# 2  
Old 05-14-2015
Hello lkeswar,

Please use code tags for commands/codes used in your posts as per forum rules. Following may help you in same.

i-
Code:
echo "20140412-s1-Potopolive_promos_20140412" | awk '{sub(/.*-/,X,$0);sub(/_.*/,X,$0);print}'

ii-
Code:
A="20140412-s1-Potopolive_promos_20140412"
B=`echo ${A##*-}`
echo ${B%%_*}

Output will be same in both the cases, hope this helps.


Thanks,
R. Singh
# 3  
Old 05-14-2015
Note: instead of B=`echo ${A##*-}` one could use: B=${A##*-}
This User Gave Thanks to Scrutinizer For This Post:
# 4  
Old 05-14-2015
Try:

echo "20140412-s1-Potopolive_promos_20140412" | awk -F "-" '{print $3}' | awk -F "_" '{print $1}'

HTH!!
# 5  
Old 05-14-2015
Quote:
Originally Posted by Mannu2525
Try:

echo "20140412-s1-Potopolive_promos_20140412" | awk -F "-" '{print $3}' | awk -F "_" '{print $1}'

HTH!!
Hello Mannu2525,

Your code can be written as follows without using 2 times awk.
Code:
echo "20140412-s1-Potopolive_promos_20140412" | awk -F"-|_" '{print $3}'

Thanks,
R. Singh
# 6  
Old 05-14-2015
Code:
[akshay@localhost tmp]$ echo '20140412-s1-Potopolive_promos_20140412' | awk 'gsub(/.*-|_.*/,"")'
Potopolive

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