UNIX for Advanced & Expert Users

grep -v will exclude matching lines, but I want something that will print all lines but exclude a matching field. The pattern that I want excluded is '/mnt/svn'

If there is a better solution than awk I am happy to hear about it, but I would like to see this done in awk as well. I know I can use sed to substitute it away, but I wanted something a little more eloquent.

Code:

awk '!/\/mnt\/svn/' file

That seems to cause the entire line which contains the pattern to be excluded I want all lines to be printed but the pattern to be removed, equivalent to

Code:

 sed 's|/mnt/svn||g'

I misread your requirement:

Code:

awk '{gsub(/\/mnt\/svn/,x)}1' file

Ah, yes gsub.. I actually knew that one! I was wondering if there is a way to do something more along the lines of

Code:

 awk '  for ( i=0; i<NF; i ++) { if $i is not /pattern/ }'

Please excuse the awful pseudo code.

Code:

awk '{ for(i=0;i<=NF;i++) { if($i !~ /\/mnt\/svn/) s=s ? s OFS $i : $i } print s; s="" }' file

Perfect! Would you mind explaining this code a bit

Code:

 s=s ? s OFS $i : $i } print s; s=""