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awk print all fields except matching regex


 
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# 8  
Old 06-17-2013
That is a conditional expression

If variable s is already defined, it appends $i value separated by OFS (space by default) else assigns just $i value.

Outside for loop the code prints s and resets s back to null.
# 9  
Old 06-17-2013
Why not just do
Code:
 awk '{ for(i=0;i<=NF;i++) { if($i !~ /\/mnt\/svn/) {print $i} }'

# 10  
Old 06-17-2013
Quote:
Originally Posted by glev2005
Why not just do
Code:
 awk '{ for(i=0;i<=NF;i++) { if($i !~ /\/mnt\/svn/) {print $i} }'

This code will print each field followed by a newline. But the code that I posted will help preserve the lines in your input file.
# 11  
Old 06-17-2013
Is /mnt/svn embedded in a longer string or is it the entire field? If it is embedded, do you want to remove the entire string or just the part /mnt/svn? If just the part, above solution will fail, as it will remove the entire field.
# 12  
Old 06-17-2013
Quote:
Originally Posted by RudiC
Is /mnt/svn embedded in a longer string or is it the entire field? If it is embedded, do you want to remove the entire string or just the part /mnt/svn? If just the part, above solution will fail, as it will remove the entire field.
It is an entire field, delimited by space. Yoda's most recent answer worked.

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