UNIX for Advanced & Expert Users

Hi all I'm trying to find a one line command that would show me all columns of the ps -ef command for all the processes started by our id that weren't started today, so where column 5 is non-numeric. I get the results I need by running three commands but was wondering if there is a way to print these with a one-line command.

First command ( prints all processes started by testid and sorts by the time column and stores in test1.txt)

Code:

ps -ef | grep testid | sort -k5 > test1.txt

Second command ( prints the 5th column only for all processes started by testid and sorts by the time column and stores in test2.txt)

Code:

ps -ef | grep testid | sort -k5 | awk '{print $5}' | grep -v [0123456789] > test2.txt

Third command ( grep test1.txt for the lines in test2.txt)

Code:

grep -f test2.txt test1.txt

I'm thinking there is a way to do this all in one command but can't figure it out

Hi,

You would need this:

Code:

ps -ef | grep -v PID | awk '$5 !~ /[0123456789]/ { print }'

Slightly modified:

Code:

ps -ef | awk '$5 !~ /^[0-9]/ &&  $5 !~ /STIME/'

-or-

Code:

ps -ef | awk '$5 ~ /^[A-Z]/ && $5 !~ /STIME/'

thanks that worked