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# 1  
Old 06-07-2011
Help with complex find syntax
I need to modify the find command below to exclude the output of the directory /usr/UDPM/PerfMgmt/shmlck



Code:
find / \( -fstype ctfs -o -fstype mntfs -o -fstype objfs -o -fstype proc -o ! local \) -prune -o -type f -perm -0002 -print 2>/dev/null

I have tried many iterations and placement of the
Code:
-name /usr/UDPM/PerfMgmt/shmlck

and have had no success. I'm just not understanding the syntax rules or it can't be done...

Help would be greatly appreciated.
Thanks in advance...Smilie
Last edited by pludi; 06-07-2011 at 01:57 PM..
# 2  
Old 06-07-2011
Try adding this option:

Code:
-path '/usr/UDPM/PerfMgmt/shmlck/' -prune

# 3  
Old 06-07-2011
Thanks for the reply, that didn't work. I've gone the more simple route and piped the output to grep with the -v shmlck and that works. It is still undecided if that is appropriate in this circumstance but it will have to do for now. I would like to get the find command to work and will continue to attempt this and will post results if positive is achieved.
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