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grep source code and exclude comments

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# 1  
Old 01-15-2010
grep source code and exclude comments
I often find myself grepping source code for a variable name and many times the name would be present in comment lines that I 'd prefer not to see. Do you guys know any tricks to filter out comments?

Example:

snippet of the source code
Code:
 
/***
 * type comment 1
 ***/
void    type_func(int rate)
{
  int   vrate = rate < 0 ? rate / (-2) : rate * (+2);
        type = BIN_RATE + vrate;        // current Bin type
        bshx = MAX_TYPE + vrate;
        // no type available
        if(!type)
                return;

plain grep results
Code:
 
$ grep type c.c
 * type comment 1
void    type_func(int rate)
        type = BIN_RATE + vrate;        // current Bin type
        // no type available
        if(!type)

I'd like to be able to see only this:
Code:
 
void    type_func(int rate)
        type = BIN_RATE + vrate;        // current Bin type
        if(!type)

# 2  
Old 01-15-2010
First eliminate comment lines and then you can remove them:

Code:
sed -e 's/#.*//;/^$/d'  FILE

I used "#" to represent a beginning of comment out line
# 3  
Old 01-15-2010
Hi.

Perhaps this might help: https://www.unix.com/unix-dummies-que...mand-help.html, changing this part:
Code:
# replace // comment with nothing
/^[ \t]*\/\//d

Last edited by Scott; 01-17-2010 at 08:28 AM..
# 4  
Old 01-15-2010
Not fully tested

Quote:
sed "/^ *\/\*/,/*\/ *$/d" file
# 5  
Old 01-16-2010
What about letting the preprocessor to do the work? Using gcc:
Quote:
cpp -fpreprocessed foo.c | grep type
HTH,
Loïc.
# 6  
Old 01-16-2010
hello ,

If I were you , I'd better try cscope
Vim/Cscope tutorial

Regards,
# 7  
Old 01-16-2010
Quote:
Originally Posted by gaurav1086
hello ,

If I were you , I'd better try cscope
Vim/Cscope tutorial

Regards,
Personally, I think the preprocessor option fits the bill perfectly.
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