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how to display only the pattern

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# 1  
Old 12-30-2003
how to display only the pattern
Hi,
I have a file with 500 Lines and I want to search for a pattern within this file which starts with sm_ and ends with ). However I just want to print the pattern only and not the entire line. How do I do it ?

Thanks,
p
# 2  
Old 12-30-2003
Hi,

GNU grep has the -o option that does what you want, it will only print the pattern, not the entire line...

from the man page:
-o, --only-matching Show only the part of a matching line that matches PATTERN.
# 3  
Old 12-30-2003
Not tested...
Code:
awk 'match($0,"sm_.*)"){print substr($0,RSTART,RLENGTH)}' $FILE

# 4  
Old 01-05-2004
Using sed...

sed 's/^.*\(PATTERN\).*$/\1/' yourFile
# 5  
Old 01-05-2004
Quote:
sed 's/^.*\(PATTERN\).*$/\1/' yourFile
does not work, since it will print all 500 lines of the file, not just those lines which contain the pattern. A possible solution using sed would be...
Code:
sed -n '/sm_.*)/{s/^.*\(sm_.*)\).*$/\1/;p;}' $FILE

# 6  
Old 01-05-2004
I must be half asleep today ;-)

This is what you want...

sed -n 's/^.*\(PATTERN\).*$/\1/p' yourFile

or even better (in terms of performance)...

sed -n '/PATTERN/s/^.*\(PATTERN\).*$/\1/p' yourFile

So for the OPs specific example...

sed -n '/sm_.*)/s/^.*\(sm_.*)\).*$/\1/p' yourFile

(which is pretty much what you have Ygor)
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