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Printing a line in a file

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# 1  
Old 11-08-2011
Printing a line in a file
Hi
I have a file having multiple lines. I want to print a particular line. How can I do this?


Thanks in advance
Ananth
# 2  
Old 11-08-2011
You already have fitting answers in your other threads:
https://www.unix.com/shell-programmin...ring-list.html
https://www.unix.com/shell-programmin...#post302565330

Where is the specific problem in this case?
# 3  
Old 11-08-2011
Hi
In those I know what to filter but in this case it can be anything so I need to display all the lines and want to select a particular line and print the same.
# 4  
Old 11-08-2011
Hi,

You can get the line in a file by grep cmd.
Code:
grep 'pattern' file

awk '$0 ~ /^pattern/{print;}' file

You can get line by line number( below example gets 10th line).
Code:
perl -ne 'if($. == 10){print;}' file

Cheers,
Ranga:-)
This User Gave Thanks to rangarasan For This Post:
Ananthdoss
# 5  
Old 11-08-2011
Anything can be everything so that does not help and a computer doesn't know. If you want to filter more than one pattern, try:
Code:
grep -E "pattern1|pattern2|pattern3" infile

This User Gave Thanks to zaxxon For This Post:
Ananthdoss
# 6  
Old 11-09-2011
Code:
awk '/ALTER TABLESPACE TEMP ADD/,/MAXINSTANCES 1/' file.txt

Moderator's Comments:
Mod Comment Use code tags, thanks. See PM.
Last edited by zaxxon; 11-09-2011 at 10:38 AM.. Reason: code tags
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