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Replace string in unix from 10th column onwards

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Special Forums UNIX and Linux Applications Replace string in unix from 10th column onwards
# 1  
Old 11-20-2009
Network Replace string in unix from 10th column onwards
Hi All,

I need to replace the last 19 bytes of the following string

My_Org_Testing_20090102_231124.txt (Text_Date_Time.txt).

I would like to derive the current time using "date +%Y%m%d_%H%M%S.txt" and replace the last 19 bytes of the above string

I would appreciate if someone could help me on this.

Thanks in advance

Regards,
Rohan
# 2  
Old 11-20-2009
Something like this.
Code:
var=My_Org_Testing_20090102_231124.txt 
echo $var| sed 's/My_Org_Testing_\(.*\)/My_Org_Testing_'$(date +%Y%m%d_%H%M%S.txt)'/

# 3  
Old 11-20-2009
Code:
$ s="My_Org_Testing_20090102_231124.txt"
$ echo ${s%???????????????????}$(date +%Y%m%d_%H%M%S.txt)

# 4  
Old 11-20-2009
Code:
 $ echo "My_Org_Testing_20090102_231124.txt"  | sed "s/.\{19\}$/$(date +%Y%m%d_%H%M%S.txt)/"

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