A way to list directories that contain specific files.


 
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Operating Systems Solaris A way to list directories that contain specific files.
# 1  
Old 01-13-2015
Oracle A way to list directories that contain specific files.

Hi everyone

My issue is this, I need to list all the sub directories in a directory that contains files that have the extension *.log, *.dat and *.out . After reviewing the output i need to delete those directories i do not need. I am running Solaris 10 in a bash shell. I have a script that I believe will list the directories that I was hoping someone here could verify the syntax but I still need a way to delete them without having to do rm -R for each one.

Code:
find ABC/ \( -name "*.out" -o -name "*.log" -o -name "*.dat" \) -print | while read f
do
  echo "${f%/*}"
done | sort -u

ABC= name of directory

Thanks in advance
Moderator's Comments:
Mod Comment Please use code tags

Last edited by jim mcnamara; 01-13-2015 at 12:04 PM.. Reason: forgot the include script
# 2  
Old 01-13-2015
You can try:

Code:
 find . -type d -exec ls *.log *.dat *.out  \; | xargs -n 1 dirname | sort -u

Also it would be considerate if you posted this on a single site, rather than a bunch of sites.

Last edited by jim mcnamara; 01-13-2015 at 12:13 PM..
# 3  
Old 01-14-2015
Quote:
Originally Posted by jim mcnamara
You can try:

Code:
 find . -type d -exec ls *.log *.dat *.out  \; | xargs -n 1 dirname | sort -u

Also it would be considerate if you posted this on a single site, rather than a bunch of sites.
This will expand *.log *.dat *.out in the directory in which find is run and will only produce the desired results if there are no files matching those three patterns in that directory.
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