How to show time minus 60 minutes?


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Operating Systems Solaris How to show time minus 60 minutes?
# 1  
How to show time minus 60 minutes?

In Redhat it is easy....
Code:
date --date="60 minutes ago"

How do you do this in Solaris?

I got creative and got the epoch time but had problems..
Code:
EPOCHTIME=`truss date 2>&1 | grep "time()" | awk '{print $3 - 900}'`
echo $EPOCHTIME
TIME=`perl -e 'print scalar(localtime("$EPOCHTIME")), "\n"'`
echo $TIME

The output from "echo $EPOCHTIME" is correct however the output from "echo $TIME" is not correct. The $EPOCHTIME variable does not carry over.

Moderator's Comments:
Mod Comment Please use code tags!

Last edited by vbe; 12-01-2011 at 11:53 AM.. Reason: use code tags next time!
# 2  
That's because nothing expands inside single quotes.

Why not just do the entire thing in perl? time() gets you current time in epoch seconds.
# 3  
My perl is about nonexistent.. LOL. I will look into it though.
# 4  
Right from perldoc -f time you get this:

Code:
use POSIX qw(strftime);
$str=strftime "%a %b %e %H:%M:%S %Y", localtime;


which you can adapt into this:

Code:
perl -e 'use POSIX qw(strftime);  print strftime "%a %b %e %H:%M:%S %Y\n", localtime(time()+$ARGV[0]);' -- -3600

The -3600 is the number of seconds to add, negative one hour.
# 5  
That is a nice one liner.. Thank you sir.
# 6  
I wouldn't call anything two terminal screens wide a "one-liner", but you're welcome.
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