Solaris

Hi,
I'd like to get the file timestamp by 'YYYYMMDD' on Solaris 9 9/05.
I can get it on the other UNIX distribution with the following command;
ls -d -l --time-style='+%Y%m%d'$FNAME | awk '{print $6; }'
but cannot get it on Solaris, it comes format error.
Could you give me any advice on this?

You need to install Gnu "ls" to make use of its specific extensions.

try this perl command:

ls |perl -ne'chomp;($d,$m,$y)=(localtime((stat($_))[9]))[3,4,5];printf "$_ %4d%02d%02d\n",$y+1900,$m,$d'

or you can try the stat command, but i'm not sure if it exists in solaris 10.

regards

Elph,

I was playing around with Solaris 10 and came up with this:

ls -E $FNAME | awk '{print substr($6,1,4) substr($6,6,2) substr($6,9,3);}'

not sure if it works with Solaris 9, but you can try it.

Dear all, I really appreciated all of your advice.

jlliagre, unfortunately, we cannot install new program on our customer's server with 'crazy' security policy.

rugdog, at my environment we don't have stat command.
Tried perl command and I got this ...
>$FILE 20100230

sdanner, unfortunately, we don't have -E option for list command.
> ls -1RaAdCxmnlhogrtucpFbqisfL@ [files]

I'll try more harder on your tips, but further advice would be so much appreciated.

Thanx,
elph

Code:

ls -l --time-style='+%Y%m%d' | perl -e 'while (<>){chomp;s/\s+/ /g; my @arr=split(" ");print "$arr[-1]\t$arr[-2]\n";}'

I have not checked this on solaris .but its on the assumption that filename is the last column and time is last before

HTH,
PL

Dear datptal, thanks for your kind advice.

Unfortunately, at this environment, we can't use "time-style".
(jlliagre had kindly advised to install GNU but we can't do it due to security reason)

If you have any furthere solution, I'd be so grateful.
Your perl script helped me a lot.

Rgs,
elph