floating point not recognized by printf in bash


 
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# 1  
Old 03-05-2010
floating point not recognized by printf in bash

Dear all,

I have the following question. Let's say that I have the following script

Code:
#!/bin/bash
value=0.4987865
a=` printf "%6.2f" $value `
b=`echo $value + $value | bc -l`
echo $a
echo $b
exit

And the exit is:

Code:
0,00
.9975730

Thus, the problem is that the printf order does not recognize the floating point arithmetic. Is there any way to fit this? In other machines it has always worked to me. Thanks in advace.

Last edited by radoulov; 03-05-2010 at 11:37 AM.. Reason: Please use code tags!
# 2  
Old 03-05-2010
Works on BASH 3.2.48 64 bit...

I get 0.50 and .9975730
# 3  
Old 03-07-2010
Quote:
Originally Posted by josegr
Thus, the problem is that the printf order does not recognize the floating point arithmetic.

printf doesn't "recognize" any arithmetic. It prints the value[s] of its arguments, nothing else.
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