Find command to get the timestamps


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# 1  
Find command to get the timestamps

I want to have the timestamps of the files containing a specific string in them.
I have tried using different combinations of find command and grep and ls but not giving the desired output.

find $HOME/bin/shells -name "*" -print -exec ls -Flt {} -exec grep -i "abc" '{}' \;

Please help.
# 2  
When you do something like this, each time that ls runs, it will be with a single file name. So using -l to sort the output doesn't make sense.

And your -name "*" is going to match everything.

find $dir -type f -exec grep -q abc {} \; -exec ls -Fl {} \;

is the syntax that comes closest to what you're trying to do. Only if the first exec succeeds will the second exec be attempted. The order is important.
# 3  
Thanks for the reply.
I am using the same command and it is funny that even though I use ls -Fl, the list is not in that order. I am trying to get the list with latest file top in the list. ls -Fl should do that. But I don't understand why it is not doing. Below is my command.

find $dir -name "*" -exec grep -q "abc" {} \; -exec ls
-Flt {} \; | awk '{print $8}' | read timestamp.

I am expecting to have timestamp = Latest file time stamp.

Please suggest. Thank you.
# 4  
It's like I said, each line is output by an individual execution of ls.
ls -lt a b c
can sort the lines that are output. But
ls -lt a ; ls -lt b ; ls -lt c
cannot.
# 5  
Since you're looking for every file, there's no need for the find command:

l -t `grep -lF 'abc' $HOME/bin/shells/*` | awk '{print $6,$7,$8}'

Last edited by oombera; 03-24-2003 at 01:27 PM..
# 6  
Sorry I do not understand.
Do you think I can get the latest file on the top of the list with the above command? (or if we modify it)?

Thanks for the help.
# 7  
I included the -t option with the "l" command to sort by date, newest first. Give it a try and see if it does what you need. Are you only trying to print the date to the screen, or other information (such as filename) too?
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