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What syntax to use with sed c\

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# 8  
Old 01-30-2009
Pludi, why does that happen?
# 9  
Old 01-30-2009
No clue. I just went by the description of the 'c' command in the man page, where it's indicated as
Code:
c \
text

as opposed to
Code:
s/regexp/replacement/

and tried it on one of our HP-UX machines (where sed complained if the newline wasn't there)
My guess would be that this was originally intended to preserve any whitespace at the start of the replacement text that otherwise might be ignored by the tokenizer.
# 10  
Old 01-30-2009
Using variables in the expression
Sorry to be a pain but I now want to use a variable instead of a line number in my script and I am getting nowhere fast with combinations of " and ' and `.

What would be the correct way to write

sed '$vLineNumberc\
replacement txt' $vfilename

(not forgetting the essential line return after the \)

Hopefully,

Susan
# 11  
Old 01-30-2009
-----
Last edited by pludi; 01-30-2009 at 08:55 AM.. Reason: see below
# 12  
Old 01-30-2009
Change each single quote to double quotes. Shell doesn't do variable substitution inside single quotes. Also, changing $vLineNumber to ${vLineNumber} can help.

HTH
# 13  
Old 01-30-2009
Back to not recognising the line return?
I tried
sed "${vLineNumber}c\
.run logon.txt" "$vScriptName" > $vScriptName2

and received this message

sed: 0602-404 Function 3c.run logon.txt cannot be parsed.

vLineNumber is successfully translating to 3 but it seems as if the line return is not being recognised anymore - or am I on the wrong track?

Without the {} the message is
sed: 0602-403 .run logon.txt is not a recognized function. So {} definitely seems necessary.

Hope you can help,

Susan
# 14  
Old 01-30-2009
Solved
An extra \ does the job.

sed "${vLineNumber}c\\
replacement text" "$vScriptName" > $vScriptName2

I got the idea from Re: Illegal variable name & carriage return

Thanks to everyone for their help.

Bye,

Susan
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