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Print lines where there's no indent on the first field

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# 1  
Old 01-15-2009
Print lines where there's no indent on the first field
Hi All,

I need a code to print those lines where there's NO indents on the 1st field
Example shown below.
I tried to use the below codes but i am not able to see the expected result.
Can any expert give any advise ?

My Code
Code:
cat filename| awk '$1 ~ /^[0-9]+$/ {print $0}'

Input
Code:
1199  ccc  zzz
1200  bbb  nnn
      1200  mmm  kkk
      1200  ppp  yyy
      1200  uuu  ttt
1201  vvv  ppp
1202  ccc  qqq


Output
Code:
1199  ccc  zzz
1200  bbb  nnn
1201  vvv  ppp
1202  ccc  qqq

# 2  
Old 01-15-2009
Code:
grep -v '^[[:blank:]]' filename

# 3  
Old 01-15-2009
Hi cfajohnson,

I tried your code but it does not get the expected result.
# 4  
Old 01-15-2009
Try this:

Code:
grep '^   *'  filename

So it was a NOT??? Didn't noticed that. Post below is correct
Last edited by angheloko; 01-15-2009 at 05:50 AM.. Reason: Wrong solution...Sorry, post below got it :)
# 5  
Old 01-15-2009
Code:
sed '/^ /d' file

# 6  
Old 01-15-2009
Which character do you use to indent? space or tab..you need to use that char after the ^ in the reg exp.

Code:
grep  -v '^ ' filename

Quote:
Originally Posted by Raynon
Hi All,

I need a code to print those lines where there's NO indents on the 1st field
Example shown below.
I tried to use the below codes but i am not able to see the expected result.
Can any expert give any advise ?

# 7  
Old 01-15-2009
Quote:
Originally Posted by Raynon
Hi cfajohnson,

I tried your code but it does not get the expected result.

So what did you get? In what way was it not what you wanted?
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