printf in bash shell not printing negative values


 
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# 1  
Old 01-14-2009
printf in bash shell not printing negative values

hi i am using printf in a script and it is not printing negative values..i have to use printf to get rid of the newline..here is my code:

Code:
fin[i]=`echo $a - $b | bc`
printf "${fin[i]}," >> test

these statements are in a loop. here is what i get when i try to subtract 4 from 8:
Code:
./scr1: line 58: printf: -4: invalid option
printf: usage: printf [-v var] format [arguments]
./scr1: line 58: printf: -4: invalid option
printf: usage: printf [-v var] format [arguments]
./scr1: line 58: printf: -4: invalid option
printf: usage: printf [-v var] format [arguments]
./scr1: line 58: printf: -4: invalid option
printf: usage: printf [-v var] format [arguments]
./scr1: line 58: printf: -4: invalid option
printf: usage: printf [-v var] format [arguments]

what can i do to get rid of this error?
# 2  
Old 01-14-2009
Hope this helps:

fin[i]=`echo $a - $b | bc`

printf "%d" ${fin[i]}

or

printf "%d\n" ${fin[i]}
# 3  
Old 01-14-2009
ok that worked! thanks a lot..
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