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extracting multiple consecutive columns using awk

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# 1  
Old 01-12-2009
extracting multiple consecutive columns using awk
Hello,
I have a matrix 200*10,000 and I need to extract the columns between 40 and 77. I dont want to write in awk all the columns. eg: awk '{print $40, $41, $42,$43 ... $77}'. I think should exist a better way to do this.
# 2  
Old 01-12-2009
Have a look at - man cut

cut -d " " -f 40-77 <filename>
# 3  
Old 01-12-2009
Hi.

The command cut should be useful. The syntax for selecting columns is compact ... cheers, drl
# 4  
Old 01-12-2009
Quote:
Originally Posted by pmm
Have a look at - man cut

cut -d " " -f 40-77 <filename>
Thanks, but 'cut' only give the first 40 columns and I want the columms after 40. I am going to check - man cut
# 5  
Old 01-13-2009
Sorry, the outfile only have 10 columns and each column is only "0.0000" still another 29 columns like this before the data starts in the original file.
# 6  
Old 01-13-2009
Can you give an example of the original data file - thanks
# 7  
Old 01-13-2009
Hi, this is the first LINE, I think the problem is with the delimiter -d " ". In the original text file I have four spaces between the numbers (when I copied here shows only one space)

0.00000 0.00000
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