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Regular Expression


 
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# 1  
Regular Expression

Hi,

I have the following file as shown below:

Replace()
{
sed -e "s+ABCDIR+$DDIR/C+g" \
-e "s+ABCDIR+$DDIR/C+g" \
-e "s + ABCDDIR+$DDIR/C"\
}

I need a Regular expression to grep 0nly ABCDIR.
if i use grep -i "ABCDIR" it will display everything.
just i need the out put as only ABCDDIR.

Please help me in solving.


Thank you very much
Ravi
# 2  
Hi,

if you want "ABCDDIR", you shouldn't use grep -i,
instead try:

Code:
grep -o "ABCDDIR"

HTH Chris
# 3  
If I use grep -o. it is showing the below message

grep: illegal option -- o
Usage: grep -hblcnsviw pattern file . . .
# 4  
You can use GNU grep, or you can use perl, which is easiest I think. This prints out ONLY the ABCDDIR text when found:
Code:
perl -n -e '/ABCDDIR/i && print $&,"\n";'

In this case, you can use perl instead of sed -- this prints out the original text as you want it:
Code:
perl -p \
-e "s+ABCDIR+$DDIR/C+gi" \
-e "s+ABCDIR+$DDIR/C+gi" \
-e "s+ABCDDIR+$DDIR/C+gi"


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