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TEST operator help

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# 1  
Old 12-24-2008
TEST operator help
Hi

I want to group
like this but syntactic is not right ...

Thanks

if [ $# = 1 -a /("$ACTION" = "PAGE" -o "$ACTION" = "PULSE"/) ]

Like this below does not work properly ..
if [ $# = 1 -a "$ACTION" = "PAGE" -o "$ACTION" = "PULSE" ]
then
:
else
usage
exit 1
fi
# 2  
Old 12-24-2008
try this

if [ $# -eq 1 -a "$ACTION" = "PAGE" -o "$ACTION" = "PULSE" ]


u need to give space before and after [
and when you compare numeric values use -eq and for strings use =
# 3  
Old 12-26-2008
Thanks for reply. Sorry didn't explain it clear. I want to group second expression so that priority was like this
If (expr1=TRUE and expr2=TRUE) second expression is ("$ACTION" = "PAGE" -o "$ACTION" = "PULSE"/)
I put '(' to group the expression but got a syntax error.
I have spaces after/before the '[ ' and ' ]'
# 4  
Old 12-26-2008
Something like this?

Code:
if [ $# -eq 1 ] && ([ "$ACTION" = "PAGE" ] || [ "$ACTION" = "PULSE" ]) ; then

Or with the ksh syntax:

Code:
if [[ "$A" -eq 2 ]] && [[ "$B" -eq 6  || "$C" -eq 9 ]] ; then

Regards
Last edited by Franklin52; 12-26-2008 at 02:19 PM.. Reason: adding alternative
# 5  
Old 12-26-2008
or:
Code:
#!/bin/ksh

ACTION='PULSE'

if [[ $# -eq 1 ]] && [[ ${ACTION} = @(PAGE|PULSE) ]]; then
   echo 'found'
fi

# 6  
Old 12-28-2008
Thanks a lot ... Works !!!
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