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how to grep a file and cut a corresponding value from the line

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# 1  
Old 12-12-2008
how to grep a file and cut a corresponding value from the line
i have to grep a file which has contents like

/Source/value/valuefile/readme.txt DefaultVersion:=1.7

I have to grep this file with "/Source/value/valuefile/readme.txt" and cut the corresponding value "1.7" from the same line

i tried grep and cut but not working.
# 2  
Old 12-12-2008
in awk and if your file is in the same format as the given example then you could try this
Code:
awk -F"=" '/\/Source\/value\/valuefile\/readme.txt/ {print $2}' filename

or with grep and cut
Code:
grep "/Source/value/valuefile/readme.txt" filename|cut -d"=" -f2

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