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Copying some part of file

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# 8  
Old 12-03-2008
Sorry for that, but if you check carefully my earlier query was actually confusing because of which i didn't get exactly what i wanted. Any ways, if its still a wrong-do then sorry once again
# 9  
Old 12-03-2008
Try this one:

Code:
awk '
/^EX ID/{i++;p=1}
/END EX ID/{p=0;print > "part"i".txt"}
p{print > "part"i".txt"}' file

Regards
# 10  
Old 12-03-2008
You may try something like this:
(use nawk or /usr/xpg4/bin/awk on Solaris)

Code:
awk '/^EX/ && !(i++%n) { 
  if (c) close(fn)
  fn = ("part" ++c ".txt")
  }  
{ print > fn }
' n=7700 infile

# 11  
Old 12-03-2008
Duplicate of this post:

https://www.unix.com/shell-programmin...#post302263651

No duplicate or cross-posting, please read the rules.
# 12  
Old 12-03-2008
Code:
nawk '/EX ID : B-Mezine/{n++}
/^$/ { next}
{
	f=sprintf("%s.txt",n)
	print >> f
}' filename

# 13  
Old 12-03-2008
Quote:
Originally Posted by Franklin52
Duplicate of this post:

https://www.unix.com/shell-programmin...#post302263651

No duplicate or cross-posting, please read the rules.

Threads merged.
# 14  
Old 12-04-2008
Hey friends first of all thanx for putting efforts. :-)
I have tried Randoulov's solution as at a glance it is the only solution which has mentioned about 7700 records.
I.e.
awk '/^EX/ && !(i++%n) {
if (c) close(fn)
fn = ("part" ++c ".txt")
}
{ print > fn }
' n=7700

But I got following error

awk: A print or getline function must have a file name.
The input line number is 1. The file is test.txt.
The source line number is 5.


What may have gone wrong, can you please guide me?
Waiting for your reply. :-)
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