Shell Programming and Scripting

Im trying to write a bash script that has an if statment that when the user enters ONLY that exact argument, will echo what follows that conditon.

For example:

Code:

for file in $1
do
 
if [ $ == "$1" ]
then
Var1=$(cat hello | egrep "that pattern" | awk '{ print $NF }')
cat $Var1
fi
done

Basically, if i specify anything other then 1 as this cmd files argument, it wont output anything.

But if i do specify 1 it will output the value that Var1 is holding... Another problem tha t i was having is that it will output when any 1 argument is passed. For example if 2 arguments are passed it wont output anything. If no arguments are passed it wont output anything. But it really doesnt matter what 1 argument i specify, it will output as long as 1 argument is givin.

What im trying to figure out from that point is how to write an if statement that looks for an exact match of that 1 argument that the user would specify.

It's not clear what you're trying to achieve.

What is the practical business problem you are solving?

string="anything.txt"

doesnt work because its of a text file extension..why?

i need to use that with an if

I have had enough of this. oxoxo is banned for continually posting homework/classroom problems.