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What is wrong with this code

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# 1  
Old 11-14-2008
What is wrong with this code
I just wanted to assign the filename to a variable

filename="abc"
datestrng=`date +%Y%m%d`
filextn="txt"


"LOCAL_FILE"${i}=${filename}"_"${datestrng}"."${filextn}

echo "LOCAL_FILE"${i}


I get the following error on 2nd last line

ksh: LOCAL_FILE1=abc_20081114.txt: not found
# 2  
Old 11-14-2008
Try changing
"LOCAL_FILE"${i}=${filename}"_"${datestrng}"."${filextn}
to
eval "LOCAL_FILE"${i}=${filename}"_"${datestrng}"."${filextn}

S.
# 3  
Old 11-14-2008
Thanks.

Well, I don't get the error but
echo "LOCAL_FILE"${i}

does not display the file name
it displays LOCAL_FILE1 (when i=1), however I wanted it to dasplay abc_20081114.txt

thanks in advance
Last edited by mqasim; 11-14-2008 at 01:42 PM..
# 4  
Old 11-14-2008
Hello mqasim,

You can subsequently print the content with:
Code:
eval echo \$LOCAL_FILE${i}

Anyway, I suspect what you are trying to do is using arrays. I do not know if your shell supports it, but if it does then an array alternative should work like this:

Code:
i=1
filename="abc"
datestrng=$(date +%Y%m%d)
filextn="txt"
LOCAL_FILE[i]=${filename}"_"${datestrng}"."${filextn}
echo ${LOCAL_FILE[i]}

Hope that works for you.

S.
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