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syntax of c shell

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# 1  
Old 11-10-2008
syntax of c shell
i have this program in bash shell:

#!/bin/bash
array=(20 20 20 20 20)
i=0
j=0
awk '/%/ {print $3}' try.txt|
while (read s)
arr[$i]=$s
i=`expr $i + 1`
echo "$i"
end

how can i convert this into c shell?
# 2  
Old 11-10-2008
Quote:
Originally Posted by npatwardhan
i have this program in bash shell:

#!/bin/bash
array=(20 20 20 20 20)
i=0
j=0
awk '/%/ {print $3}' try.txt|
while (read s)

That's not the way to do it in bash:

Code:
while read s; do

Quote:
arr[$i]=$s
i=`expr $i + 1`

Why are you using an external command for integer arithmetic in bash?

Code:
i=$(( $i + 1 ))

Quote:
echo "$i"
end

how can i convert this into c shell?

Don't.

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