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Swapping or switching 2 lines using sed

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Top Forums Shell Programming and Scripting Swapping or switching 2 lines using sed
# 8  
Old 10-17-2008
If you also want to swap line 15 with line 17:

Code:
#!/bin/sh
 
line=3
line1=15
 
awk -v var="$line" -v var1="$line1" 'NR==var {
  s=$0
  getline;s=$0"\n"s
  getline;print;print s
  next
}
NR==var1 {
  s=$0
  getline;s=$0"\n"s
  getline;print;print s
  next
}
1' file

Regards
# 9  
Old 10-17-2008
Bug
Quote:
Originally Posted by Franklin52
If you also want to swap line 15 with line 17:

Code:
#!/bin/sh
 
line=3
line1=15
 
awk -v var="$line" -v var1="$line1" 'NR==var {
  s=$0
  getline;s=$0"\n"s
  getline;print;print s
  next
}
NR==var1 {
  s=$0
  getline;s=$0"\n"s
  getline;print;print s
  next
}
1' file

Regards
I understand what that does...but I was hoping to switch lines var with var1. This switches var with var+2 and var1 with var1+2...If this code isn't built for that...then don't worry about trying to modify this code to do that. I was just hoping it was easy to do using this code.
# 10  
Old 10-17-2008
To swap line 3 with line 10:

Code:
#!/bin/sh
 
line=3
line1=10

awk -v var="$line" -v var1="$line1" 'NR==var {
  s=$0
  for(i=var+1;i<var1;i++){
    getline;s=$0"\n"s
  }
  getline;print;print s
  next
}1' file

Regards
# 11  
Old 10-22-2008
Quote:
Originally Posted by Franklin52
To swap line 3 with line 10:

Code:
#!/bin/sh
 
line=3
line1=10
 
awk -v var="$line" -v var1="$line1" 'NR==var {
  s=$0
  for(i=var+1;i<var1;i++){
    getline;s=$0"\n"s
  }
  getline;print;print s
  next
}1' file

Regards

Thanks that works perfectly!Smilie
# 12  
Old 10-22-2008
Another one:

(use nawk or /usr/xpg4/bin/awk on Solaris)
Code:
awk 'NR == FNR {
  if (NR ~ "^("ln1"|"ln2")$")
    _[++c] = $0
  next
  }
FNR ~ "^("ln1"|"ln2")$" { $0 = _[c--] } 
1' ln1=3 ln2=5 infile infile


or:

Code:
awk 'NR == ln1, NR == ln2 { 
  _[++c] = $0
  if (NR == ln2 && j = c) 
    while (++i <= c)
      print _[NR ~ "^("ln1"|"ln2")$"?j--:i]
  next
}1' ln1=3 ln2=5 infile

Last edited by radoulov; 10-22-2008 at 01:26 PM.. Reason: addition
# 13  
Old 10-22-2008
Hammer & Screwdriver
Quote:
Originally Posted by radoulov
Another one:

(use nawk or /usr/xpg4/bin/awk on Solaris)
Code:
awk 'NR == FNR {
  if (NR ~ "^("ln1"|"ln2")$")
    _[++c] = $0
  next
  }
FNR ~ "^("ln1"|"ln2")$" { $0 = _[c--] } 
1' ln1=3 ln2=5 infile infile


or:

Code:
awk 'NR == ln1, NR == ln2 { 
  _[++c] = $0
  if (NR == ln2 && j = c) 
    while (++i <= c)
      print _[NR ~ "^("ln1"|"ln2")$"?j--:i]
  next
}1' ln1=3 ln2=5 infile

I had trouble getting either of these to work (i'm probably running it in the wrong shell)...I was able to get the latter to work by passing my variables from bash into the awk statement using "'"s...see below modified code.
Code:
#!/bin/bash
ln1=3
ln2=5
awk 'NR=="'"$ln1"'", NR=="'"$ln2"'" { 
  _[++c] = $0
  if (NR=="'"$ln2"'" && j = c) 
    while (++i<=c)
      print _[NR~"^("'"$ln1"'"|""'"$ln2"'")$"?j--:i]
  next
}1' infile

# 14  
Old 10-22-2008
Quote:
Originally Posted by LaTortuga
I had trouble getting either of these to work (i'm probably running it in the wrong shell)[...]
This is strange,
what error/wrong behavior you got?

This is on my system:

Code:
% print -l {1..10}>infile
% cat infile 
1
2
3
4
5
6
7
8
9
10
% awk 'NR == FNR {
quote>   if (NR ~ "^("ln1"|"ln2")$")
quote>     _[++c] = $0
quote>   next
quote>   }
quote> FNR ~ "^("ln1"|"ln2")$" { $0 = _[c--] } 
quote> 1' ln1=3 ln2=5 infile infile
1
2
5
4
3
6
7
8
9
10
% awk 'NR == ln1, NR == ln2 { 
quote>   _[++c] = $0
quote>   if (NR == ln2 && j = c) 
quote>     while (++i <= c)
quote>       print _[NR ~ "^("ln1"|"ln2")$"?j--:i]
quote>   next
quote> }1' ln1=3 ln2=5 infile
1
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3
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