extract/select pattern from input


 
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# 1  
Old 10-14-2008
Question extract/select pattern from input

Hey,

examples of the input (text line):

/bla/blMOasdn234.adanif24/blabla.rar
/bla/blMOasdn234.adanif24/blabla23124.bin
/bla/bla/bla/bla/bla/bla.bin

and what I need to do is extract/select only the dir path so the output would be:

/bla/blMOasdn234.adanif24/
/bla/blMOasdn234.adanif24/
/bla/bla/bla/bla/bla/

I was trying to use sed and I could only get the oposite result, like

Code:
echo /test/test2/test3/noname.rar | sed 's/\/.*\///'

result noname.rar :/

Last edited by TehOne; 10-14-2008 at 03:25 PM..
# 2  
Old 10-14-2008
Code:
sed 's_\(.*/\).*_\1_'

Regards
# 3  
Old 10-14-2008
Code:
awk -F"/" '{for(i=1;i<NF;i++) {printf $i"/"} print ""}' filename

# 4  
Old 10-14-2008
Thank you, works fine!
# 5  
Old 10-15-2008
Code:
sed 's/\(.*\)\(\/.*\)/\1/' filename

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