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Replacing the part of file name?

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# 1  
Old 10-07-2008
Replacing the part of file name?
Hi All

One of my script generate following files. These files has static TIMESTAMP 20080227.

AccAdd_20080227_1000.dat
AccBal_20080227_1000.dat
Acc_20080227_1000.dat
AccGrpMem_20080227_1000.dat
AccToCust_20080227_1000.dat

What i need to do is, once the file has been generated, it should change the timestamo (20080227) & replace it with the parameter which i am passing. for example if i pass script parameter ... 20070909... then it should be like..

AccAdd_20070909_1000.dat
AccBal_20070909_1000.dat
Acc_20070909_1000.dat
AccGrpMem_20070909_1000.dat
AccToCust_20070909_1000.dat

Can someone tell me which comand should be ussed?

Regards,

Amit
# 2  
Old 10-07-2008
if you have Python , you can use the script here
example usage
Code:
# ls -1 Acc*dat
AccAdd_20080227_1000.dat
AccBal_20080227_1000.dat
AccToCust_20080227_1000.dat
Acc_20080227_1000.dat

# parameter="20090101"
# filerenamer.py -p "_.*_" -e _"$parameter"_ -l "Acc*.dat"
==>>>>  [ /home/AccToCust_20080227_1000.dat ]==>[ /home/AccToCust_20090101_1000.dat ]
==>>>>  [ /home/test/Acc_20080227_1000.dat ]==>[ /home/Acc_20090101_1000.dat ]
==>>>>  [ /home/AccBal_20080227_1000.dat ]==>[ /home/AccBal_20090101_1000.dat ]
==>>>>  [ /home/AccAdd_20080227_1000.dat ]==>[ /home/AccAdd_20090101_1000.dat ]

# filerenamer.py -p "_.*_" -e _"$parameter"_  "Acc*.dat"
/home/AccToCust_20080227_1000.dat  is renamed to  /home/AccToCust_20090101_1000.dat
/home/Acc_20080227_1000.dat  is renamed to  /home/Acc_20090101_1000.dat
/home/AccBal_20080227_1000.dat  is renamed to  /home/AccBal_20090101_1000.dat
/home/AccAdd_20080227_1000.dat  is renamed to  /home/AccAdd_20090101_1000.dat

# ls -1 Acc*dat
AccAdd_20090101_1000.dat
AccBal_20090101_1000.dat
AccToCust_20090101_1000.dat
Acc_20090101_1000.dat

# 3  
Old 10-07-2008
Java
Hi Ghost,

No i do not have python. I have tried using sed command. But it is not working.

Regards,

Amit
# 4  
Old 10-07-2008
Amit,

Try using the below in your script

timeparam=$1
ls Acc* | while read filename
do
firstname=`echo $filename | awk -F'_' '{print $1}'`
lastname=`echo $filename | awk -F'_' '{print $3}'`
newfilename=`echo $firstname`_`echo $timeparam`_`echo $lastname`
mv $filename $newfilename
done
# 5  
Old 10-07-2008
Try this, first without the last pipe command (| sh) to be sure you get the right mv command:

Code:
ls -1 *_20080227_* |
awk -F"_" -v old="20080227" -v new="20070909" '$2==old{print "mv "$0 " "$1"_"new"_"$3}' | sh

Regards
# 6  
Old 10-07-2008
Quote:
Originally Posted by Amit.Sagpariya
Hi Ghost,

No i do not have python. I have tried using sed command. But it is not working.

Regards,

Amit
Code:
# echo AccToCust_20090101_1000.dat |sed 's|\(.*\)_\(.*\)_\(.*\)|\1_20090201_\3|'
AccToCust_20090201_1000.dat

# 7  
Old 10-08-2008
Thank you guys... I got expected result. Thank you veru much
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