Shell Programming and Scripting

Hi guys, so I have another issue. Can I use sed to replace spaces in a string or variable with %20

I am having trouble with using curl on URL's containing spaces

Thanks!

post sample input and output record

Code:

string=$( printf "%s\n" "$string" | sed 's/ /%20/g' )

Or. with bash or ksh93:

Code:

string=${string// /%20}

this is a sample of the code I have to get the file "GetSeries.php.xml" from thetvdb.com

Code:

series_name="green hornet"

curl -s -o /Users/rtipton/Desktop/GetSeries.php.xml "http://thetvdb.com/api/GetSeries.php?seriesname=$series_name"

When I run this, I get a bunch of results in the xml for tv shows including "green" in the title. Curl doesn't include anything after the first space in the URL.

I'm not sure what output I could provide in this instance, let me know if I can give more

Thanks again Vid

Hey thanks cfajohnson, that did the trick, the second suggestion works perfectly!

Thanks again for being so helpful guys, I really appreciate it.

you can try something like this

Code:

 
series_name=`echo "$series_name"|sed 's/ /%20/g'`

Nice this works as well. Too many good options here! You guys are good, thanks again!

Rob