condition inside a for loop

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# 1  
Old 09-25-2008
condition inside a for loop

I have a for loop in my script as shown below.

for file_path in $file_list ; do code


Can i restrict the number of files parsing to the variable file_path as 50?
That is, even if I have some 100 files in file_list, I need to take only 50 files for the loop every time.

Is that possible? Can someone help me with this?

# 2  
Old 09-25-2008
for file_path in `cat filelist.txt|head -50`
        echo $file_path

# 3  
Old 09-25-2008
head -50 file | while read file_path

# 4  
Old 09-25-2008
But.. this doesn't solve my request.
Because.. i read it from a variable $file_list.
This contains the input as following:

echo $file_list
aaa.txt bbb.txt ccc.txt ddd.txt .......and so on.

So all file names will be in a single line. so head -50 will return all the files.. right?

any other way to get the first 50 names in the variable?
# 5  
Old 09-25-2008
Just maintain a counter in the loop, and exit when it reaches 50.

for file_path in $file_list; do
  : : : stuff
  n=`expr $n + 1`
  case $n in 50) break;; esac

# 6  
Old 09-25-2008
filelist="1 2 3 4 5 6 7 8 9 10"
for filepath in `echo $filelist|cut -d" " -f1-5`
        echo $filepath

Instead of 5 use 50.
# 7  
Old 09-25-2008
Assuming that spacing in the variable is regular. If it might contain tabs or newlines, awk might be a better solution. Or maybe

perl -le '$,=" "; print @ARGV[0..49]' "$@"

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