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Shell Programming and Scripting

Problem in argument passing

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# 1  
Old 09-23-2008
Problem in argument passing
Hell all,

i have a problem in argument passing.

print()
{
a=$1
b=$2
c=$3

echo $a
echo $b
echo $c
}

x="1 2 3"
y="4 5 6"
z="7 8 9"

print $x $y $z.



i am passing x,y and z to the function print.

it has to take the x , y and z . and it has to print as bellow

1 2 3
4 5 6
7 8 9


but it is printing as bellow.
1
2
3.

Since the values are seperated by space. it is accepting the first variable x alone.

how to solve this?.
# 2  
Old 09-23-2008
Quote the arguments properly.
# 3  
Old 09-23-2008
use double quotes around variables and arguments.
# 4  
Old 09-23-2008
And don't use the name print as a function name, in ksh it's a built-in function!

Regards
# 5  
Old 09-23-2008
Change the function call to look like below :

print "${x}" "${y}" "${z}"

This should have worked , and yes as said by Franklin "print" is a buitin word in shell.
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