Shell Programming and Scripting

Hi
How to create a directory structure with getting input from a file.

I have file in that following lines are written.

./activemq-4.1.2/activemq-core-4.1.2.jar
./activemq-4.1.2/backport-util-concurrent-2.1.jar
./camel-1.4.0/apache-camel-1.4.0.jar
./camel-1.4.0/lib/activation-1.1.jar
./camel-1.4.0/lib/camel-amqp-1.4.0.jar
./camel-1.4.0/lib/camel-atom-1.4.0.jar
./camel-1.4.0/lib/camel-bam-1.4.0.jar
./camel-1.4.0/lib/camel-core-1.4.0.jar
./camel-1.4.0/lib/camel-csv-1.4.0.jar
./camel-1.4.0/lib/camel-cxf-1.4.0.jar

Now how to create that directory structure with empty file name.

Thanks
Joy

Assuming you want to create the directories:

./activemq-4.1.2/
./activemq-4.1.2/
etc...

Code:

sed 's!\(.*/\).*!mkdir -p \1!' file | sh

Regards

Thanks Franklin52 for replying.

Can we do this with awk and cut rather than sed . I am not familiar with sed and its usage.

Thanks
Joy

With awk you can something like:

Code:

awk -F"/" '{print "mkdir -p "$1"/"$2}' file | sh

Regards

Hi

I have tried similar like this, but one problem is there. it is creating 1 or 2 level folders(but it can be 'n' level).

Thanks
Joy

The input file you post has only one level..!? Never mind, this should work:

Code:

awk 'BEGIN{FS=OFS="\"}{$NF="";print "mkdir -p $0}' file | sh

Regards

Code:

awk -F/ -v OFS=/ '{ $NF="" }1' | uniq | xargs mkdir -p

Franklin was faster, our solutions are almost identical.