Shell Programming and Scripting

program name--test

#!/bin/bash

output1=`/home/user/a.c`
output2=`/home/user/a.c`

k=`$output1 + 1`

m=`$output2 + 1`

echo $k
echo $m

---------------------------------------------------------------------------
prgram name--a.c

#include<stdio.h>

int main()
{
int i,j;
printf("Enter Values ::");
scanf("%d %f",);
snprintf(s, 100, "echo %d","echo %d",i,j);
system(s);
return 0
}
-------------------------------------------------------------------------

my requirement is to access the variable from C program as a simple input,pass the value of two variables to the script
which will manipulate the value and display

main thing is : not to execute c Program first,.we have to excute ./test first in console
Problem is I did not pass those two variable to the script.
Is there any way to pass the value of those variable from C program?please help me out...i an sending error message..thanks to all


[user@localhost ~]$ chmod 777 a.c
[user@localhost ~]$ chmod 777 test
[user1@localhost ~]$ ./test
/home/user/a.c: line 3: syntax error near unexpected token `('
/home/user/a.c: line 3: `int main()'
/home/user/test.c: line 3: syntax error near unexpected token `('
/home/users/test.c: line 3: `int main()'

one second thought: This has to be homework.

export the variables in shell script - in C call getenv() to retrieve the variable's value.

Code:

export plpl="SOMEVALUE"

Code:

#include <unistd.h>
..........
........
printf("%s\n", getenv("plpl");