Shell Programming and Scripting

Hi all,

My simple AWK code does

Code:

C = A - B

If C can be a negative number, how awk printf formating handles it using string format specifier.

Thanks in advance
Kanu

%d would be the normal one to use for whole integers.

Code:

awk 'BEGIN { printf("%d\n",C) }'

My code:

Code:

#!/bin/awk -f
BEGIN {

# Enter the numbers
        a = 2;
        b = 3;
        c = a - b;

                printf ("The first number is%d\n",a);
                printf ("The second number is%d\n",b);
                printf ("The result is%d\n",c);


exit;
}

result:

Code:

The first number is2
The second number is3
The result is-1

i want there the whole number using format specifier...

means value of C should come around to be 1 (absolute value)

If you want the absolute value of the number you want to print,
why don't you store it as an absolute value in the first place,
i.e., c = abs (a - b)
note that you should include the external library stdlib.h for using this function with integer values.
when you printf c you'll get a nonsigned number
else you can incorporate abs in the printf command

printf ("The result is %d\n", abs(c))

something like that

OK! thanks budd! how to do it with a format specifier??

Try %u it is the unsigned integer format specifier used in C programming just like printf command.
I hope it will work with awk.