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search for the matched pattern by tracing back from the line

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# 8  
Doesn't tytalus' solution work for you? If you want it to just print the line number of the first match with the same time stamp, that's a trivial modification.

awk '/data11/{print c[$1];}{c[$1] = NR }' logfile.txt

I'm still wondering, do you want both the matching line and the first one with the same time stamp, or just the first one?

Assuming the latter (or actually, either way), it's probably simpler if you add the desired output formatting directly to the awk script.

awk '/data11/{print c[$1];}
    {split ($0, t, ":"); c[$1]=$5 " " t[1] " " t[2] ":" t[3] }' logfile.txt >>msg.txt

With the sample data you posted, the data value from $5 is just a dash, so I imagine you really wanted $6 (and then the cut -f5 in your original code should be cut -f6, correspondingly).
# 9  
hi, actually,my need is like,in the given file i have to find the line which has the keyword "Not authenticated by System" and
"authenticated by System".and i have to get the corresponding names which here is 'sharmila' and 'shivu'.
If it is not authenticated i have to make the status as 'Failure' otherwise as 'Success'.
So here In case of 'Not authenticated i can read the name'sharmila' from the same line.But in case of 'authenticated' i have to trace back the line which has the same may be in is my code.

for i in $(grep -n "authenticated by System" logfile.txt|cut -d: -f1)
sed -n "${i},${i}p" logfile.txt| /usr/xpg4/bin/grep -q "NOT authenticated by System"
if [ $? -eq 0 ]
sed -n "${i},${i}p" logfile.txt|cut -d" " -f5 | sed '1s/^.//' | sed '$s/.$//' >> msg.txt
echo "Failure" >> msg.txt

sed -n "${i},${i}p" logfile.txt| /usr/xpg4/bin/grep -q "getCredentials"
if [ $? -eq 0 ]
sed -n "${i},${i}p" logfile.txt|cut -d" " -f4 >> msg.txt
echo "Success" >> msg.txt


so my need is in the else part how i can get that particular mathched line.
As i am new to unix ,i dont know how i can do this using awk.
Can anyone tell me ,whether in the given code i can get that line or how i can apply the awk here.

[22/Jul/2008:19:35:45-20401-23-1] getCredentials - sharmila
[22/Jul/2008:19:35:45-20401-23-2] DoLogin - Setting variables
[22/Jul/2008:19:35:45-20401-23-1] DoLogin - data authenticated by System.
[22/Aug/2008:29:37:14-20401-56-1] DoLogin - User 'sharmila' was NOT authenticated by System.
[12/Jan/2008:19:35:45-20401-23-1] getCredentials - shivu
[22/Jul/2008:19:35:45-20401-23-2] DoLogin - Setting varaibles for all
[22/Jul/2008:19:35:45-20401-23-1] DoLogin - User authenticated by System
[22/Aug/2008:29:37:14-20401-56-1] DoLogin - User 'shivu' was NOT authenticated by System.

# 10  
nawk '/NOT authenticated by system/ { who=$5; gsub(/'"'"'/, "", who); print who, "Failure"; next }
/authenticated by system/ { print user, "Success"; next; }
/getCredentials/ { user=$4 }' logfile.txt >>msg.txt

I'm not sure if I captured your requirements correctly, but this should hopefully at least help you get going.

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