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how to get number char from a string


 
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# 1  
Old 07-16-2008
how to get number char from a string

for example:

i hav a string like :

/rmsprd/arch01/rmsprd/rmsprdarch72736.log

how I can extract

my_num=72736?

I know I can

echo "/rmsprd/arch01/rmsprd/rmsprdarch72736.log" | tr "/" " " | awk '{ print $4 }' to get rmsprdarch72736.log
# 2  
Old 07-16-2008
Tools will it always be in same format?

Code:
> echo "/rmsprd/arch01/rmsprd/rmsprdarch72736.log" | cut -d"/" -f5 | cut -d"." -f1
rmsprdarch72736

if you know it will always be ten characters (rmsprdarch), then
Code:
> echo "/rmsprd/arch01/rmsprd/rmsprdarch72736.log" | cut -d"/" -f5 | cut -d"." -f1 | cut -c11-
72736

# 3  
Old 07-16-2008
Something like:

Code:
my_num=`echo $string | sed 's/.*[a-z]\([0-9].*\)\..*/\1/'`

Regards
# 4  
Old 07-16-2008
If you are using ksh93 you do not need to invoke external utilities like cut or sed. The following will work
Code:
$ str="/rmsprd/arch01/rmsprd/rmsprdarch72736.log"
$ print $str
/rmsprd/arch01/rmsprd/rmsprdarch72736.log
$ print ${str/*([[:print:]])({5}(\d)).log/\2}
72736
$

# 5  
Old 07-16-2008
echo "/rmsprd/arch01/rmsprd/rmsprdarch72736.log" | cut -d"/" -f5 | cut -d"." -f1|tr -d [:alpha:]

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