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Shell Programming and Scripting

Finding missing sequential file names

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# 1  
Old 07-03-2008
Finding missing sequential file names
So, I've got a ton of files that I want to go through (ie something like 300,000), and they're all labeled sequentially. However I'm not 100% positive that they are all there.

Is there any way of running through a sequence of numbers, checking if the file is in the folder, if not appending it to a file so I can figure out if any are missing?
# 2  
Old 07-03-2008
Lets see if i have understood you correctly:

The files you have are called:

file1x
file2x
file3x
...

but maybe there are missing numbers which you want to find. Correct?

If so, the following example should do the trick:

Code:
#! /bin/ksh

typeset -i iMinNum=1
typeset -i iMaxNum=9
typeset -i iWork=0
typeset    fLog=./mylogfile

(( iWork = iMinNum ))
while [ $iWork -le $iMaxNum ] ; do
     if [ ! -f ./file${iWork}x ] ; then
          print - "File file${iWork}x is missing" >> $fLog
     fi
     (( iWork += 1 ))
done

I hope this helps.

bakunin
# 3  
Old 07-03-2008
Try this ....:
Assume that the file names are file1 file2 file3....file10

Code:
seq -f "file%g" 1 10  | xargs ls -l | grep -v '^-'

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