I want to build a script

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# 1  
Old 07-08-2002
I want to build a script

I have this script

sed -e '$q' -e 's/I/D/g' <inputfile> outfile

which replaces I by D...

I have to run this script in 90 files which their filename starts with CD*. I want to call all these files and execute this command once.
Or schedule it to be executed at 1600hrs every day.

I want to output to the same i.e I'm modifying these file so input file has to have the same file as the output.

thanx forwarded
# 2  
Old 07-08-2002
you can do this

for file in `ls CD*`
sed -e 's/I/D/g' < $file > $file.out
mv $file.out $file

If you want to run it at a specific time, use the cron command there have been plenty of posts on this site about it already.
# 3  
Old 07-08-2002
Just curious what your $q is doing? From the syntax it looks like another sed command....just something I learnt the other day...

Inside single quotes, what you see is what you get. No character has any special meaning inside single quotes. So variables won't expand. Use double quotes
# 4  
Old 07-08-2002
He actually doesn't want to change the last line. 'q' is a command that makes sed quit. '$' addresses the last line. So when the last line is encountered, sed exits so that second command never runs. See this thread.
# 5  
Old 07-08-2002
Ah, very clever....context does help.
# 6  
Old 07-15-2002
MySQL Its working

txs a lot...its working..

I want build a script which will alert me by outlook mail about backup status
# 7  
Old 07-31-2002
perl -pi -e

The -i option in Perl will edit the specified file "in place", so you don't have to mess with moving files around.

% echo "eat food" >> test.txt
% echo "eat more food" >> test2.txt
% perl -pi -e 's/food/pie/g' *
% cat test.txt
eat pie
% cat test2.txt
eat more pie

-i takes an optional argument. If specified, a backup will be saved with the argument as the file's extension.

% perl -pi'.bak' -e 's/pie/chicken/g' *
% ls
test.txt test.txt.bak test2.txt test2.txt.bak
% cat test.txt
eat chicken
% cat test.txt.bak
eat pie
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