how to parse value of the variable


 
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# 1  
Old 06-12-2008
how to parse value of the variable

I have a variable which has a full path to the file, for example :
A=/t1/bin/f410pdb
Does anybody know the command to parce this variable and assign the result to 3 other variables so each subdirectory name will be in a new variable like this
B=t1
C=bin
D=f410pdb
Many thanks -A
# 2  
Old 06-12-2008
Hammer & Screwdriver One approach

> A=/t1/bin/f410pdb
> B=$(echo "$A" | cut -d"/" -f2)
> C=$(echo "$A" | cut -d"/" -f3)
> D=$(echo "$A" | cut -d"/" -f4)
> echo $A
/t1/bin/f410pdb
> echo $B
t1
> echo $C
bin
> echo $D
f410pdb
# 3  
Old 06-12-2008
Thanks a lot -A
# 4  
Old 06-12-2008
Another ...

Code:
$ A=/t1/bin/f410pdb oIFS=$IFS IFS=/
$ set -- $A
$ IFS=$oIFS
$ echo $2
t1
$ echo $3
bin
$ echo $4
f410pdb

With Z-Shell:

Code:
$ A=/t1/bin/f410pdb a=(${(s:/:)A})
$ print $a[1]
t1
$ print $a[2]
bin
$ print $a[3]
f410pdb


Last edited by radoulov; 06-12-2008 at 12:43 PM..
# 5  
Old 06-12-2008
Thank again for help

The code works perfectly
Would you mind to explain what
oIFS=$IFS IFS=/ does. Cheers -A
# 6  
Old 06-13-2008
Save the current Internal Field Separator in oIFS, set it temporarily to '/' so the shell can split the string, restore ASAP the standard value.
For more information:

Code:
man sh|less -pIFS

This User Gave Thanks to radoulov For This Post:
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