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Shell Programming and Scripting

help with looping

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# 1  
Old 05-23-2008
help with looping
Code:
vesselNames values:
xxx
yyy
zzz

Code:
vesselPlanned values:
xxx
zzz
zzz
zzz


Code:
OIFS=""
OIFS=$IFS
IFS="\n"

for var in $vesselNames
do
        vesselNameList=`echo $var|cut -d : -f1`
        vesselNameConnectionType=`echo $var|cut -d : -f2`
        vesselNameQuantityList=`echo $var|cut -d : -f3`

if [ "$vesselNameList" != "NA" ]
        then
                if [ "$vesselNameList" = "$vesselPlanned" ]
                then
                result="$file, $carrier, $date, $vesselNameList, $vesselNameConnectionType, $vesselNameQuantityList, $vesselA
utoPlannedName, $name"
                fi
        else
                result="$file, $carrier, $date, $vesselNameList, $vesselNameConnectionType, $vesselNameQuantityList, ZZZZZ, $
vesselAutoPlannedName, $name"
        fi


echo $result
done



it suppose to loop 3 times only, however it shows this instead:
Code:
xxx
xxx
xxx
xxx
xxx
zzz
zzz
zzz
zzz
zzz
zzz
zzz

# 2  
Old 05-23-2008
It's obvious that you're providing us partial data and a partial script, therefore it's impossible to figure out what's going on, let alone, what's going wrong.

But I'd bet you've got nested loops that are screwed up.
# 3  
Old 05-23-2008
Hammer & Screwdriver Only can see part of issue, but perhaps expected to see 12 outputs
As Dave said, only part of coding visible. However, to see 12 outputs is not entirely crazy. You have three vessel_names and four vessel_plans : thus 3 x 4 = 12.
You showed part of how you build the three members of vessel_names, but not the vessel_plans.
If you want to debug this, insert an echo line like:
Code:
if [ "$vesselNameList" != "NA" ]
        then
                echo "$vesselNameList" "$vesselPlanned" 
                if [ "$vesselNameList" = "$vesselPlanned" ]

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